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Kebun Pak Bambang berbentuk persegi panjang yaitu panjang (x+5) meter dan lebar (7- x) meter. Maka luas maksimum kebun Pak Bambang adalah…m2

Rani Maharani

Soal

pembahasan

Langkah-langkah perhitungan:

Luas kebun = (x+5)(7-x) = -x² + 2x + 35

Turunan pertama: dL/dx = -2x + 2

Turunan kedua: d²L/dx² = -2

Tiap-tiap turunan tersebut kita substitusikan x = 1 untuk mendapatkan:

Titus stasioner: dL/dx = 0 ketika x = 1

Luas maksimum: -1² + 2(1) + 35 = 36 m²

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