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Segitiga siku siku ABC, dengan panjang sisi yang saling berpenyiku 20 cm dan 32 cm. Hitunglah luas segitiga tersebut!

Rani Maharani

Soal

Pembahasan

Diketahui:

Sisi AB = 20 cm
Sisi BC = 32 cm

Ditanyakan: Luas segitiga ABC

Solusi:

Hitung panjang sisi AC menggunakan teorema Pythagoras:

AC² = AB² + BC²
AC² = 20² + 32²
AC² = 400 + 1024
AC² = 1424
AC = √1424
AC = 37.73 cm (diambil dua angka di belakang koma)

Luas segitiga ABC dapat dihitung dengan rumus:

Luas = 1/2 x alas x tinggi
Alas = AB = 20 cm
Tinggi = BC = 32 cm
Luas = 1/2 x 20 cm x 32 cm
Luas = 320 cm²

Jadi, luas segitiga ABC adalah 320 cm².

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